ATPS Etapa 3 4 e 5 SARA SUBORBITAL

ETAPA 3

• PASSO 2

1. y = vo.t + ½ . gt²

8 = 0.t + ½ . 9,8t²

8 = 9,8t²/2

4,9t² = 8

t² = 8/4,9

t² = 1,63

t = 1,28 segundos

2. v = v0 + g . t

v = 0 + 9,8 . 1,27

v = 12,45 m/s

3. Mach 9 = Mach 1 x 9

Mach 9 = 1.225 x 9

Mach 9 = 11.025 km/h = 3.062,5 m/s

Vy² = Voy² + 2g.(∆y)

0 = (3.062,5)² + 2 .(- 9,8) .(∆y)

0 = 9.378.906,25 – 19,6.∆y

19,6∆y = 9.378.906,25

∆y = 9.378.906,25/19,6

∆y = 478.515,62 m ou 478,5 km

• PASSO 3

v = vo + g . t

0 = 11,025 + (-9,8) . t

9,8t = 11,025

t = 11,025/9,8

t = 1,125 segundos 

ETAPA 4

• PASSO 1

y = yo + yoy – gt²/2

304,8 = 0 + 0 – 9,8t²/2

304,8 = - 9,8t²/2

304,8 = -4,9t²

t² = 304,8/4,9

t²= 62,20

t = 7,88 segundos

• PASSO 2

x = xo + Vox.t

x= 0 + 111,1 . 7,88

x = 875,5 metros

• PASSO 3

3.1. v = v0 + g . t

v = 0 + 9,8 . 7,88

v = 77,22 m/s

3.2. (77,32)² + (111,1)² = V²

V² = 12345,432 + 5978,3824

V² = 18323,814

V² = 135.36 m/s

ETAPA 5

• PASSO 1

X = Xo + gt Vy = Vyo² + 2.g.x

0 = 1382,9 – 9,8T 0 = (Vyo)² + 2 . (9,8) . 9757,2

9,8T = 1382,9 Vyo² = 1912415,12

T = 1382,9/9,8 Vyo = 1382,9 m/s

T = 141,112 segundos

V = Vx² + Vy²

V = 1912415,12 + 5737222,6

V = 2765 m/s.

• PASSO 2

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