Calculo Numérico - Atps
Artigos Científicos: Calculo Numérico - Atps. Pesquise 860.000+ trabalhos acadêmicosPor: Alencar42 • 20/11/2013 • 601 Palavras (3 Páginas) • 291 Visualizações
ETAPA 1
PASSO 2
Desafio A
a)
v (2.24, 1.12)
u (1.12, 0.56)
v (2.24, 1.12) + u (1.12, 0.56) = 0
(2.24v, 1.12v) + (1.12u, 0.56u) = 0
2.24v + 1.12u = 0
1.12v + 0.56u = 0
2.24 1.12 0
1.12 0.56 0
M² = 1.12 / 2.24 = 0.5
1.12 – 2.24 * 0.5 = 0
0.56 – 1.12 * 0.5 = 0
2.24 1.12 0
0 0 0
v = 0
u = 0
I - L.I. – Linearmente Independente
b)
u (2.4, 1.92)
v (-1.42, 1.68)
z (-0.48, -2.12)
(2.4u, 1.92u)
(-1.42v, 1.68v)
(-0.48z, -2.12z)
(2.4u, 1.92u) + (-1.42v, 1.68v) + (-0.48z, -2.12z) = 0
2.4u – 1.42v – 0.48z = 0
1.92u + 1.68v – 2.12z = 0
2.4 - 1.42 - 0.48 0
1.92 1.68 - 2.12 0
M² = 1.92 / 2.4 = 0.8
1.92 – 2.4 * 0.8 = 0
1.68 – (- 1.42) * 0.8 = 2.816
-2.12 – ( - 0.48) * 0.8 = - 1.736
2.4 - 1.42 - 0.48 0
0 2.816 - 1.736 0
M³ = 2.816 / -1,42 = - 1.983
2.816 – (- 1.42) * (- 1.983) = 0
- 1.736 – ( - 0.48) * (- 1.983) = - 2.687
2.4 - 1.42 - 0.48 0
0 0 - 2.687 0
-2.687z = 0
z = 0
v = 0
u = 0
II - L.I. - Linearmente Independente
c)
w (-0.5, -2.26)
u (2.52, 2.02)
v (1.24, -0.74)
w(-0.5, -2.26) + u(2.52, 2.02) + v(1.24, -0.74) = 0
(0.5w, -2.26w) + (2.52u, 2.02u) + (1.24v, -0.74v) = 0
0.5w + 2.52u + 1.24v = 0
-2.26w +2.02u – 0.74v = 0
0.5 2.52 1.24 0
-2.26 2.02 -0.74 0
M² = -2.26 / 0.5 = -4.52
-2.26 - 0.5 * (-4.52) = 0
2.02 – 2.52 * (-4.52) = 13.41
-0.74 – 1.24 * (-4.52) = 4.864
0.5 2.52 1.24 0
0 13.41 4.864 0
M³ = 13.41 / 2.52 = 5.321
13.41 – 2.52 * 5.321 = 0
4.864 – 1.24 * 5.321 = 1.734
0.5 2.52 1.24 0
0 0 1.734 0
1.734v = 0
v = 0
u = 0
w = 0
III - L.I. – Linearmente Independente
Desafio B
u (4, 7, -1)
v (3, 10, 11)
u (4, 7, -1) + v (3, 10, 11) = 0
(4u, 7u, -u) + (3v, 10v, 11v) = 0
4 3 0
...